Base | Representation |
---|---|
bin | 110011001110010100… |
… | …1001101101011010001 |
3 | 101111221020121101010101 |
4 | 1212130221031223101 |
5 | 3300241032411032 |
6 | 122311225332401 |
7 | 10642646354536 |
oct | 1463451155321 |
9 | 344836541111 |
10 | 110002232017 |
11 | 42719435057 |
12 | 1939b637101 |
13 | a4b0acbb22 |
14 | 5477604d8d |
15 | 2cdc3d8de7 |
hex | 199ca4dad1 |
110002232017 has 2 divisors, whose sum is σ = 110002232018. Its totient is φ = 110002232016.
The previous prime is 110002232009. The next prime is 110002232023. The reversal of 110002232017 is 710232200011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109412762176 + 589469841 = 330776^2 + 24279^2 .
It is a cyclic number.
It is not a de Polignac number, because 110002232017 - 23 = 110002232009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110002231985 and 110002232003.
It is not a weakly prime, because it can be changed into another prime (110002232047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001116008 + 55001116009.
It is an arithmetic number, because the mean of its divisors is an integer number (55001116009).
Almost surely, 2110002232017 is an apocalyptic number.
It is an amenable number.
110002232017 is a deficient number, since it is larger than the sum of its proper divisors (1).
110002232017 is an equidigital number, since it uses as much as digits as its factorization.
110002232017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 19.
Adding to 110002232017 its reverse (710232200011), we get a palindrome (820234432028).
The spelling of 110002232017 in words is "one hundred ten billion, two million, two hundred thirty-two thousand, seventeen".
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