Base | Representation |
---|---|
bin | 10000000000011110011… |
… | …111011111100011100011 |
3 | 10220011100111201110002221 |
4 | 100000132133133203203 |
5 | 121010321414344341 |
6 | 2201202122451511 |
7 | 142321412631643 |
oct | 20003637374343 |
9 | 3804314643087 |
10 | 1100023199971 |
11 | 394576467523 |
12 | 159237663b97 |
13 | 7c96883c077 |
14 | 3b3545c6523 |
15 | 1d932a34ed1 |
hex | 1001e7df8e3 |
1100023199971 has 2 divisors, whose sum is σ = 1100023199972. Its totient is φ = 1100023199970.
The previous prime is 1100023199887. The next prime is 1100023200041. The reversal of 1100023199971 is 1799913200011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100023199971 - 213 = 1100023191779 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100023799971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550011599985 + 550011599986.
It is an arithmetic number, because the mean of its divisors is an integer number (550011599986).
Almost surely, 21100023199971 is an apocalyptic number.
1100023199971 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100023199971 is an equidigital number, since it uses as much as digits as its factorization.
1100023199971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30618, while the sum is 43.
Adding to 1100023199971 its reverse (1799913200011), we get a palindrome (2899936399982).
The spelling of 1100023199971 in words is "one trillion, one hundred billion, twenty-three million, one hundred ninety-nine thousand, nine hundred seventy-one".
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