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1100030012313 = 34713681570253
BaseRepresentation
bin10000000000011110111…
…001011110101110011001
310220011100222112112212220
4100000132321132232121
5121010330140343223
62201202524454253
7142321524554001
oct20003671365631
93804328475786
101100030012313
1139457a29a761
121592399aa389
137c96a085a3b
143b35547b001
151d93342d6e3
hex1001ee5eb99

1100030012313 has 16 divisors (see below), whose sum is σ = 1498025323776. Its totient is φ = 717696357120.

The previous prime is 1100030012293. The next prime is 1100030012329. The reversal of 1100030012313 is 3132100300011.

It is not a de Polignac number, because 1100030012313 - 213 = 1100030004121 is a prime.

It is a super-3 number, since 3×11000300123133 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100030012292 and 1100030012301.

It is not an unprimeable number, because it can be changed into a prime (1100030012353) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1643895 + ... + 2214147.

It is an arithmetic number, because the mean of its divisors is an integer number (93626582736).

Almost surely, 21100030012313 is an apocalyptic number.

It is an amenable number.

1100030012313 is a deficient number, since it is larger than the sum of its proper divisors (397995311463).

1100030012313 is a wasteful number, since it uses less digits than its factorization.

1100030012313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 583984.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1100030012313 its reverse (3132100300011), we get a palindrome (4232130312324).

The spelling of 1100030012313 in words is "one trillion, one hundred billion, thirty million, twelve thousand, three hundred thirteen".

Divisors: 1 3 47 141 13681 41043 570253 643007 1710759 1929021 26801891 80405673 7801631293 23404893879 366676670771 1100030012313