Base | Representation |
---|---|
bin | 1001000110001011101111… |
… | …01110011101011111111111 |
3 | 2121211022222020210012111121 |
4 | 10203011313232131133333 |
5 | 10110220004332200011 |
6 | 110313320524131411 |
7 | 4133134424065522 |
oct | 443056756353777 |
9 | 77738866705447 |
10 | 20003671365631 |
11 | 6412566a9a408 |
12 | 22b0a19096b67 |
13 | b21451ac0135 |
14 | 4d227baa6bb9 |
15 | 24a51c342e71 |
hex | 123177b9d7ff |
20003671365631 has 2 divisors, whose sum is σ = 20003671365632. Its totient is φ = 20003671365630.
The previous prime is 20003671365619. The next prime is 20003671365719. The reversal of 20003671365631 is 13656317630002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20003671365631 - 25 = 20003671365599 is a prime.
It is a super-2 number, since 2×200036713656312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20003671365331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001835682815 + 10001835682816.
It is an arithmetic number, because the mean of its divisors is an integer number (10001835682816).
Almost surely, 220003671365631 is an apocalyptic number.
20003671365631 is a deficient number, since it is larger than the sum of its proper divisors (1).
20003671365631 is an equidigital number, since it uses as much as digits as its factorization.
20003671365631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 408240, while the sum is 43.
Adding to 20003671365631 its reverse (13656317630002), we get a palindrome (33659988995633).
The spelling of 20003671365631 in words is "twenty trillion, three billion, six hundred seventy-one million, three hundred sixty-five thousand, six hundred thirty-one".
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