Base | Representation |
---|---|
bin | 11001000000110000011110… |
… | …011111101010010010100001 |
3 | 112102111012112010020222001202 |
4 | 121000300132133222102201 |
5 | 103404243040241020223 |
6 | 1025542440123010545 |
7 | 32112320122213013 |
oct | 3100603637522241 |
9 | 472435463228052 |
10 | 110003214001313 |
11 | 32061112586a26 |
12 | 10407439969a55 |
13 | 494c349102b99 |
14 | 1d24280b321b3 |
15 | cab681979428 |
hex | 640c1e7ea4a1 |
110003214001313 has 2 divisors, whose sum is σ = 110003214001314. Its totient is φ = 110003214001312.
The previous prime is 110003214001253. The next prime is 110003214001367. The reversal of 110003214001313 is 313100412300011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 57528083664529 + 52475130336784 = 7584727^2 + 7243972^2 .
It is a cyclic number.
It is not a de Polignac number, because 110003214001313 - 212 = 110003213997217 is a prime.
It is not a weakly prime, because it can be changed into another prime (110003214001613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001607000656 + 55001607000657.
It is an arithmetic number, because the mean of its divisors is an integer number (55001607000657).
Almost surely, 2110003214001313 is an apocalyptic number.
It is an amenable number.
110003214001313 is a deficient number, since it is larger than the sum of its proper divisors (1).
110003214001313 is an equidigital number, since it uses as much as digits as its factorization.
110003214001313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 110003214001313 its reverse (313100412300011), we get a palindrome (423103626301324).
The spelling of 110003214001313 in words is "one hundred ten trillion, three billion, two hundred fourteen million, one thousand, three hundred thirteen".
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