Base | Representation |
---|---|
bin | 1010000000010011011011… |
… | …0101110110011001100001 |
3 | 1102221121210000010001020012 |
4 | 2200010312311312121201 |
5 | 2420212134310044134 |
6 | 35221252113054305 |
7 | 2213514315354365 |
oct | 240046665663141 |
9 | 42847700101205 |
10 | 11000331331169 |
11 | 356123a292a24 |
12 | 1297b30857395 |
13 | 61a432c719bb |
14 | 2a05c15832a5 |
15 | 1412258066ce |
hex | a0136d76661 |
11000331331169 has 2 divisors, whose sum is σ = 11000331331170. Its totient is φ = 11000331331168.
The previous prime is 11000331331139. The next prime is 11000331331229. The reversal of 11000331331169 is 96113313300011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10704544368400 + 295786962769 = 3271780^2 + 543863^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000331331169 - 28 = 11000331330913 is a prime.
It is a super-2 number, since 2×110003313311692 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (11000331331139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500165665584 + 5500165665585.
It is an arithmetic number, because the mean of its divisors is an integer number (5500165665585).
Almost surely, 211000331331169 is an apocalyptic number.
It is an amenable number.
11000331331169 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000331331169 is an equidigital number, since it uses as much as digits as its factorization.
11000331331169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 32.
The spelling of 11000331331169 in words is "eleven trillion, three hundred thirty-one million, three hundred thirty-one thousand, one hundred sixty-nine".
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