11000402141121 has 10 divisors (see below), whose sum is σ = 16432699494882. Its totient is φ = 7333601427360.

The previous prime is 11000402141119. The next prime is 11000402141137. The reversal of 11000402141121 is 12114120400011.

11000402141121 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 0 + 402 + 141 + 121 = 666.

11000402141121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 10987534415025 + 12867726096 = 3314745^2 + 113436^2 .

It is not a de Polignac number, because 11000402141121 - 2¹ = 11000402141119 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000402141094 and 11000402141103.

It is not an unprimeable number, because it can be changed into a prime (11000402141161) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 67903716840 + ... + 67903717001.

Almost surely, 2^{11000402141121} is an apocalyptic number.

It is an amenable number.

11000402141121 is a deficient number, since it is larger than the sum of its proper divisors (5432297353761).

11000402141121 is an equidigital number, since it uses as much as digits as its factorization.

11000402141121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135807433853 (or 135807433844 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 18.

Adding to 11000402141121 its reverse (12114120400011), we get a palindrome (23114522541132).

The spelling of 11000402141121 in words is "eleven trillion, four hundred two million, one hundred forty-one thousand, one hundred twenty-one".