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11000402141137 is a prime number
BaseRepresentation
bin1010000000010011101100…
…0011111101111111010001
31102221121221221100120020121
42200010323003331333101
52420212310422004022
635221303122510241
72213516135263423
oct240047303757721
942847857316217
1011000402141137
113561276257562
121297b50505381
1361a4448350a6
142a05cab36813
1514122bb422c7
hexa013b0fdfd1

11000402141137 has 2 divisors, whose sum is σ = 11000402141138. Its totient is φ = 11000402141136.

The previous prime is 11000402141119. The next prime is 11000402141161. The reversal of 11000402141137 is 73114120400011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7160981352001 + 3839420789136 = 2676001^2 + 1959444^2 .

It is an emirp because it is prime and its reverse (73114120400011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000402141137 - 219 = 11000401616849 is a prime.

It is not a weakly prime, because it can be changed into another prime (11000402141737) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500201070568 + 5500201070569.

It is an arithmetic number, because the mean of its divisors is an integer number (5500201070569).

Almost surely, 211000402141137 is an apocalyptic number.

It is an amenable number.

11000402141137 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000402141137 is an equidigital number, since it uses as much as digits as its factorization.

11000402141137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672, while the sum is 25.

Adding to 11000402141137 its reverse (73114120400011), we get a palindrome (84114522541148).

The spelling of 11000402141137 in words is "eleven trillion, four hundred two million, one hundred forty-one thousand, one hundred thirty-seven".