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11000402405513 = 161331912137211
BaseRepresentation
bin1010000000010011101100…
…0100111110100010001001
31102221121221221211222220022
42200010323010332202021
52420212311003434023
635221303132310225
72213516140444253
oct240047304764211
942847857758808
1011000402405513
113561276418154
121297b50612375
1361a4448c8521
142a05caba4cd3
1514122bb957c8
hexa013b13e889

11000402405513 has 8 divisors (see below), whose sum is σ = 11010676856256. Its totient is φ = 10990132238800.

The previous prime is 11000402405507. The next prime is 11000402405533. The reversal of 11000402405513 is 31550420400011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11000402405513 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000402405533) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4078478 + ... + 6215688.

It is an arithmetic number, because the mean of its divisors is an integer number (1376334607032).

Almost surely, 211000402405513 is an apocalyptic number.

It is an amenable number.

11000402405513 is a deficient number, since it is larger than the sum of its proper divisors (10274450743).

11000402405513 is a wasteful number, since it uses less digits than its factorization.

11000402405513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2142015.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 11000402405513 its reverse (31550420400011), we get a palindrome (42550822805524).

The spelling of 11000402405513 in words is "eleven trillion, four hundred two million, four hundred five thousand, five hundred thirteen".

Divisors: 1 1613 3191 2137211 5147083 3447321343 6819840301 11000402405513