Search a number
-
+
11000505011 = 29379327759
BaseRepresentation
bin10100011111010111…
…00110001010110011
31001101122101112222112
422033223212022303
5140012112130021
65015322555535
7536413515116
oct121753461263
931348345875
1011000505011
114735553261
122170068bab
131064073482
14764da257d
15445b3dd5b
hex28fae62b3

11000505011 has 4 divisors (see below), whose sum is σ = 11379832800. Its totient is φ = 10621177224.

The previous prime is 11000505007. The next prime is 11000505013. The reversal of 11000505011 is 11050500011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11000505011 - 22 = 11000505007 is a prime.

It is a super-2 number, since 2×110005050112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000505013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189663851 + ... + 189663908.

It is an arithmetic number, because the mean of its divisors is an integer number (2844958200).

Almost surely, 211000505011 is an apocalyptic number.

11000505011 is a deficient number, since it is larger than the sum of its proper divisors (379327789).

11000505011 is an equidigital number, since it uses as much as digits as its factorization.

11000505011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 379327788.

The product of its (nonzero) digits is 25, while the sum is 14.

Subtracting 11000505011 from its reverse (11050500011), we obtain a triangular number (49995000 = T9999).

The spelling of 11000505011 in words is "eleven billion, five hundred five thousand, eleven".

Divisors: 1 29 379327759 11000505011