Base | Representation |
---|---|
bin | 110011001110011011… |
… | …1100101110100110011 |
3 | 101111221111200212010101 |
4 | 1212130313211310303 |
5 | 3300243014012242 |
6 | 122311442213231 |
7 | 10643023402633 |
oct | 1463467456463 |
9 | 344844625111 |
10 | 110006000947 |
11 | 42720579777 |
12 | 193a0954217 |
13 | a4b181b46b |
14 | 5477d066c3 |
15 | 2cdc8d09b7 |
hex | 199cde5d33 |
110006000947 has 2 divisors, whose sum is σ = 110006000948. Its totient is φ = 110006000946.
The previous prime is 110006000939. The next prime is 110006001067. The reversal of 110006000947 is 749000600011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110006000947 - 23 = 110006000939 is a prime.
It is not a weakly prime, because it can be changed into another prime (110006000347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55003000473 + 55003000474.
It is an arithmetic number, because the mean of its divisors is an integer number (55003000474).
Almost surely, 2110006000947 is an apocalyptic number.
110006000947 is a deficient number, since it is larger than the sum of its proper divisors (1).
110006000947 is an equidigital number, since it uses as much as digits as its factorization.
110006000947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 110006000947 its reverse (749000600011), we get a palindrome (859006600958).
The spelling of 110006000947 in words is "one hundred ten billion, six million, nine hundred forty-seven", and thus it is an aban number.
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