Base | Representation |
---|---|
bin | 11001000000110110110100… |
… | …001011000001100010010001 |
3 | 112102111212002110012200202212 |
4 | 121000312310023001202101 |
5 | 103404401010124004301 |
6 | 1025545523334121505 |
7 | 32112650565356315 |
oct | 3100666413014221 |
9 | 472455073180685 |
10 | 110010020141201 |
11 | 32063a95461624 |
12 | 104088191b0295 |
13 | 494cb921c13ab |
14 | 1d24728a27b45 |
15 | cab92e24d4bb |
hex | 640db42c1891 |
110010020141201 has 2 divisors, whose sum is σ = 110010020141202. Its totient is φ = 110010020141200.
The previous prime is 110010020141173. The next prime is 110010020141243. The reversal of 110010020141201 is 102141020010011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84260484781201 + 25749535360000 = 9179351^2 + 5074400^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110010020141201 is a prime.
It is not a weakly prime, because it can be changed into another prime (110010020141291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005010070600 + 55005010070601.
It is an arithmetic number, because the mean of its divisors is an integer number (55005010070601).
Almost surely, 2110010020141201 is an apocalyptic number.
It is an amenable number.
110010020141201 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010020141201 is an equidigital number, since it uses as much as digits as its factorization.
110010020141201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 110010020141201 its reverse (102141020010011), we get a palindrome (212151040151212).
The spelling of 110010020141201 in words is "one hundred ten trillion, ten billion, twenty million, one hundred forty-one thousand, two hundred one".
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