Base | Representation |
---|---|
bin | 1010000000010101111101… |
… | …0010110001010011101011 |
3 | 1102221200112022011001101201 |
4 | 2200011133102301103223 |
5 | 2420220032030014011 |
6 | 35221443315225031 |
7 | 2213540166100123 |
oct | 240053722612353 |
9 | 42850468131351 |
10 | 11001010001131 |
11 | 3561558393797 |
12 | 129809bba8177 |
13 | 61a510753467 |
14 | 2a0647767c83 |
15 | 1412651b3cc1 |
hex | a015f4b14eb |
11001010001131 has 2 divisors, whose sum is σ = 11001010001132. Its totient is φ = 11001010001130.
The previous prime is 11001010001081. The next prime is 11001010001173. The reversal of 11001010001131 is 13110001010011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11001010001131 - 29 = 11001010000619 is a prime.
It is a super-2 number, since 2×110010100011312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11001013001131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500505000565 + 5500505000566.
It is an arithmetic number, because the mean of its divisors is an integer number (5500505000566).
Almost surely, 211001010001131 is an apocalyptic number.
11001010001131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001010001131 is an equidigital number, since it uses as much as digits as its factorization.
11001010001131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3, while the sum is 10.
Adding to 11001010001131 its reverse (13110001010011), we get a palindrome (24111011011142).
The spelling of 11001010001131 in words is "eleven trillion, one billion, ten million, one thousand, one hundred thirty-one".
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