110010123131131 has 4 divisors (see below), whose sum is σ = 110078579961072. Its totient is φ = 109941666301192.

The previous prime is 110010123130991. The next prime is 110010123131171. The reversal of 110010123131131 is 131131321010011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 110010123131131 - 2¹¹ = 110010123129083 is a prime.

It is a super-2 number, since 2×110010123131131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110010123131099 and 110010123131108.

It is not an unprimeable number, because it can be changed into a prime (110010123131171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34228412560 + ... + 34228415773.

It is an arithmetic number, because the mean of its divisors is an integer number (27519644990268).

Almost surely, 2^{110010123131131} is an apocalyptic number.

110010123131131 is a deficient number, since it is larger than the sum of its proper divisors (68456829941).

110010123131131 is an equidigital number, since it uses as much as digits as its factorization.

110010123131131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68456829940.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 110010123131131 its reverse (131131321010011), we get a palindrome (241141444141142).

The spelling of 110010123131131 in words is "one hundred ten trillion, ten billion, one hundred twenty-three million, one hundred thirty-one thousand, one hundred thirty-one".