Base | Representation |
---|---|
bin | 1010000000010101111111… |
… | …1001011000010001011011 |
3 | 1102221200120000012020220020 |
4 | 2200011133321120101123 |
5 | 2420220042122402303 |
6 | 35221444320201523 |
7 | 2213540351112456 |
oct | 240053771302133 |
9 | 42850500166806 |
10 | 11001020122203 |
11 | 3561563076911 |
12 | 12980a34692a3 |
13 | 61a512888167 |
14 | 2a0648c4049d |
15 | 141266012a53 |
hex | a015fe5845b |
11001020122203 has 4 divisors (see below), whose sum is σ = 14668026829608. Its totient is φ = 7334013414800.
The previous prime is 11001020122091. The next prime is 11001020122217. The reversal of 11001020122203 is 30222102010011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11001020122203 - 225 = 11000986567771 is a prime.
It is a super-3 number, since 3×110010201222033 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11001020102203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1833503353698 + ... + 1833503353703.
It is an arithmetic number, because the mean of its divisors is an integer number (3667006707402).
Almost surely, 211001020122203 is an apocalyptic number.
11001020122203 is a deficient number, since it is larger than the sum of its proper divisors (3667006707405).
11001020122203 is an equidigital number, since it uses as much as digits as its factorization.
11001020122203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3667006707404.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 11001020122203 its reverse (30222102010011), we get a palindrome (41223122132214).
The spelling of 11001020122203 in words is "eleven trillion, one billion, twenty million, one hundred twenty-two thousand, two hundred three".
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