11001020137 has 2 divisors, whose sum is σ = 11001020138. Its totient is φ = 11001020136.

The previous prime is 11001020131. The next prime is 11001020203. The reversal of 11001020137 is 73102010011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6695166976 + 4305853161 = 81824^2 + 65619^2 .

It is a cyclic number.

It is not a de Polignac number, because 11001020137 - 2¹⁵ = 11000987369 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11001020137.

It is not a weakly prime, because it can be changed into another prime (11001020131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500510068 + 5500510069.

It is an arithmetic number, because the mean of its divisors is an integer number (5500510069).

Almost surely, 2^11001020137 is an apocalyptic number.

It is an amenable number.

11001020137 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001020137 is an equidigital number, since it uses as much as digits as its factorization.

11001020137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 16.

Adding to 11001020137 its reverse (73102010011), we get a palindrome (84103030148).

The spelling of 11001020137 in words is "eleven billion, one million, twenty thousand, one hundred thirty-seven".