Base | Representation |
---|---|
bin | 110011001110100011… |
… | …1101100010110000001 |
3 | 101111221210122022020221 |
4 | 1212131013230112001 |
5 | 3300300104100303 |
6 | 122312112503041 |
7 | 10643104313032 |
oct | 1463507542601 |
9 | 344853568227 |
10 | 110010221953 |
11 | 427229a2005 |
12 | 193a224aa81 |
13 | a4b26687b8 |
14 | 54786c4a89 |
15 | 2cdce664bd |
hex | 199d1ec581 |
110010221953 has 2 divisors, whose sum is σ = 110010221954. Its totient is φ = 110010221952.
The previous prime is 110010221933. The next prime is 110010221969. The reversal of 110010221953 is 359122010011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109291070464 + 719151489 = 330592^2 + 26817^2 .
It is a cyclic number.
It is not a de Polignac number, because 110010221953 - 29 = 110010221441 is a prime.
It is not a weakly prime, because it can be changed into another prime (110010221933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005110976 + 55005110977.
It is an arithmetic number, because the mean of its divisors is an integer number (55005110977).
Almost surely, 2110010221953 is an apocalyptic number.
It is an amenable number.
110010221953 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010221953 is an equidigital number, since it uses as much as digits as its factorization.
110010221953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 25.
Adding to 110010221953 its reverse (359122010011), we get a palindrome (469132231964).
The spelling of 110010221953 in words is "one hundred ten billion, ten million, two hundred twenty-one thousand, nine hundred fifty-three".
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