Base | Representation |
---|---|
bin | 10000000000100011011… |
… | …000011111011010000001 |
3 | 10220011120020010001011221 |
4 | 100000203120133122001 |
5 | 121011003421003213 |
6 | 2201214213235041 |
7 | 142323430225060 |
oct | 20004330373201 |
9 | 3804506101157 |
10 | 1100105250433 |
11 | 394608809222 |
12 | 15925b032a81 |
13 | 7c97c839837 |
14 | 3b3614641d7 |
15 | 1d939d4138d |
hex | 1002361f681 |
1100105250433 has 16 divisors (see below), whose sum is σ = 1299156848640. Its totient is φ = 911589742800.
The previous prime is 1100105250421. The next prime is 1100105250473. The reversal of 1100105250433 is 3340525010011.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 1100105250433 - 217 = 1100105119361 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100105250398 and 1100105250407.
It is not an unprimeable number, because it can be changed into a prime (1100105250473) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2399803 + ... + 2821216.
It is an arithmetic number, because the mean of its divisors is an integer number (81197303040).
Almost surely, 21100105250433 is an apocalyptic number.
It is an amenable number.
1100105250433 is a deficient number, since it is larger than the sum of its proper divisors (199051598207).
1100105250433 is an equidigital number, since it uses as much as digits as its factorization.
1100105250433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5222028.
The product of its (nonzero) digits is 1800, while the sum is 25.
The spelling of 1100105250433 in words is "one trillion, one hundred billion, one hundred five million, two hundred fifty thousand, four hundred thirty-three".
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