Base | Representation |
---|---|
bin | 10000000000100011100… |
… | …111010001000101101011 |
3 | 10220011120111101211122102 |
4 | 100000203213101011223 |
5 | 121011010413431242 |
6 | 2201214432244015 |
7 | 142323505160111 |
oct | 20004347210553 |
9 | 3804514354572 |
10 | 1100109123947 |
11 | 39460aa14479 |
12 | 1592603a060b |
13 | 7c980594962 |
14 | 3b361b91ab1 |
15 | 1d93a358e32 |
hex | 100239d116b |
1100109123947 has 2 divisors, whose sum is σ = 1100109123948. Its totient is φ = 1100109123946.
The previous prime is 1100109123943. The next prime is 1100109123959. The reversal of 1100109123947 is 7493219010011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100109123947 - 22 = 1100109123943 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1100109123947.
It is not a weakly prime, because it can be changed into another prime (1100109123943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550054561973 + 550054561974.
It is an arithmetic number, because the mean of its divisors is an integer number (550054561974).
Almost surely, 21100109123947 is an apocalyptic number.
1100109123947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100109123947 is an equidigital number, since it uses as much as digits as its factorization.
1100109123947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 38.
The spelling of 1100109123947 in words is "one trillion, one hundred billion, one hundred nine million, one hundred twenty-three thousand, nine hundred forty-seven".
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