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11001108924041 is a prime number
BaseRepresentation
bin1010000000010110010100…
…1100001000011010001001
31102221200210012021212010012
42200011211030020122021
52420220232341032131
635221501211401305
72213542506655115
oct240054514103211
942850705255105
1011001108924041
1135615a9209a65
121298109153235
1361a5280aa922
142a0656958745
1514126dc0452b
hexa0165308689

11001108924041 has 2 divisors, whose sum is σ = 11001108924042. Its totient is φ = 11001108924040.

The previous prime is 11001108924011. The next prime is 11001108924053. The reversal of 11001108924041 is 14042980110011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10701567255625 + 299541668416 = 3271325^2 + 547304^2 .

It is an emirp because it is prime and its reverse (14042980110011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001108924041 - 210 = 11001108923017 is a prime.

It is a super-2 number, since 2×110011089240412 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11001108923989 and 11001108924007.

It is not a weakly prime, because it can be changed into another prime (11001108924011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500554462020 + 5500554462021.

It is an arithmetic number, because the mean of its divisors is an integer number (5500554462021).

Almost surely, 211001108924041 is an apocalyptic number.

It is an amenable number.

11001108924041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001108924041 is an equidigital number, since it uses as much as digits as its factorization.

11001108924041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 32.

The spelling of 11001108924041 in words is "eleven trillion, one billion, one hundred eight million, nine hundred twenty-four thousand, forty-one".