Base | Representation |
---|---|
bin | 10000000000100011101… |
… | …110011110000110011011 |
3 | 10220011120121221202220121 |
4 | 100000203232132012123 |
5 | 121011011404343001 |
6 | 2201214540534111 |
7 | 142323530213266 |
oct | 20004356360633 |
9 | 3804517852817 |
10 | 1100111012251 |
11 | 394610a94159 |
12 | 159260b51337 |
13 | 7c980aa62b4 |
14 | 3b362123cdd |
15 | 1d93a5cd6a1 |
hex | 10023b9e19b |
1100111012251 has 2 divisors, whose sum is σ = 1100111012252. Its totient is φ = 1100111012250.
The previous prime is 1100111012141. The next prime is 1100111012261. The reversal of 1100111012251 is 1522101110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100111012251 - 215 = 1100110979483 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100111012261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055506125 + 550055506126.
It is an arithmetic number, because the mean of its divisors is an integer number (550055506126).
Almost surely, 21100111012251 is an apocalyptic number.
1100111012251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100111012251 is an equidigital number, since it uses as much as digits as its factorization.
1100111012251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 16.
Adding to 1100111012251 its reverse (1522101110011), we get a palindrome (2622212122262).
The spelling of 1100111012251 in words is "one trillion, one hundred billion, one hundred eleven million, twelve thousand, two hundred fifty-one".
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