Base | Representation |
---|---|
bin | 1010000000010110010101… |
… | …0100000101101101100011 |
3 | 1102221200210100012211201101 |
4 | 2200011211110011231203 |
5 | 2420220233404311042 |
6 | 35221501324215231 |
7 | 2213542533464056 |
oct | 240054524055543 |
9 | 42850710184641 |
10 | 11001111010147 |
11 | 35615aa404315 |
12 | 129810999a517 |
13 | 61a52865b2cb |
14 | 2a0656d3ca9d |
15 | 14126deb76b7 |
hex | a0165505b63 |
11001111010147 has 2 divisors, whose sum is σ = 11001111010148. Its totient is φ = 11001111010146.
The previous prime is 11001111010091. The next prime is 11001111010261. The reversal of 11001111010147 is 74101011110011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11001111010147 - 239 = 10451355196259 is a prime.
It is not a weakly prime, because it can be changed into another prime (11001111013147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555505073 + 5500555505074.
It is an arithmetic number, because the mean of its divisors is an integer number (5500555505074).
Almost surely, 211001111010147 is an apocalyptic number.
11001111010147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001111010147 is an equidigital number, since it uses as much as digits as its factorization.
11001111010147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 19.
Adding to 11001111010147 its reverse (74101011110011), we get a palindrome (85102122120158).
The spelling of 11001111010147 in words is "eleven trillion, one billion, one hundred eleven million, ten thousand, one hundred forty-seven".
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