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11001111021217 is a prime number
BaseRepresentation
bin1010000000010110010101…
…0100001000011010100001
31102221200210100020101220101
42200011211110020122201
52420220233410134332
635221501324342401
72213542533541252
oct240054524103241
942850710211811
1011001111021217
1135615aa411669
1212981099a4a01
1361a528663365
142a0656d42b29
1514126debaae7
hexa01655086a1

11001111021217 has 2 divisors, whose sum is σ = 11001111021218. Its totient is φ = 11001111021216.

The previous prime is 11001111021193. The next prime is 11001111021233. The reversal of 11001111021217 is 71212011110011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5765141947041 + 5235969074176 = 2401071^2 + 2288224^2 .

It is a cyclic number.

It is not a de Polignac number, because 11001111021217 - 215 = 11001110988449 is a prime.

It is a super-2 number, since 2×110011110212172 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11001111021194 and 11001111021203.

It is not a weakly prime, because it can be changed into another prime (11001111021317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555510608 + 5500555510609.

It is an arithmetic number, because the mean of its divisors is an integer number (5500555510609).

Almost surely, 211001111021217 is an apocalyptic number.

It is an amenable number.

11001111021217 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001111021217 is an equidigital number, since it uses as much as digits as its factorization.

11001111021217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28, while the sum is 19.

Adding to 11001111021217 its reverse (71212011110011), we get a palindrome (82213122131228).

The spelling of 11001111021217 in words is "eleven trillion, one billion, one hundred eleven million, twenty-one thousand, two hundred seventeen".