Base | Representation |
---|---|
bin | 10000000000100011101… |
… | …110110101110101100001 |
3 | 10220011120122010201021102 |
4 | 100000203232311311201 |
5 | 121011011421000343 |
6 | 2201214543004145 |
7 | 142323531066605 |
oct | 20004356656541 |
9 | 3804518121242 |
10 | 1100111109473 |
11 | 394611050202 |
12 | 159260b99655 |
13 | 7c980b0b61c |
14 | 3b36214b505 |
15 | 1d93a5ec3b8 |
hex | 10023bb5d61 |
1100111109473 has 2 divisors, whose sum is σ = 1100111109474. Its totient is φ = 1100111109472.
The previous prime is 1100111109457. The next prime is 1100111109481. The reversal of 1100111109473 is 3749011110011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 912697443904 + 187413665569 = 955352^2 + 432913^2 .
It is an emirp because it is prime and its reverse (3749011110011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1100111109473 - 24 = 1100111109457 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100111109973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055554736 + 550055554737.
It is an arithmetic number, because the mean of its divisors is an integer number (550055554737).
Almost surely, 21100111109473 is an apocalyptic number.
It is an amenable number.
1100111109473 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100111109473 is an equidigital number, since it uses as much as digits as its factorization.
1100111109473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756, while the sum is 29.
Adding to 1100111109473 its reverse (3749011110011), we get a palindrome (4849122219484).
The spelling of 1100111109473 in words is "one trillion, one hundred billion, one hundred eleven million, one hundred nine thousand, four hundred seventy-three".
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