Base | Representation |
---|---|
bin | 11001000000110111111011… |
… | …101111111100001110111011 |
3 | 112102111222012010211200221011 |
4 | 121000313323233330032323 |
5 | 103404410440034014042 |
6 | 1025550242432454351 |
7 | 32113022416455604 |
oct | 3100677357741673 |
9 | 472458163750834 |
10 | 110011221001147 |
11 | 320645512a5464 |
12 | 10408ab33aa3b7 |
13 | 4950023c270cb |
14 | 1d248002dcdab |
15 | cab99e8a8a17 |
hex | 640dfbbfc3bb |
110011221001147 has 2 divisors, whose sum is σ = 110011221001148. Its totient is φ = 110011221001146.
The previous prime is 110011221001079. The next prime is 110011221001151. The reversal of 110011221001147 is 741100122110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110011221001147 - 215 = 110011220968379 is a prime.
It is not a weakly prime, because it can be changed into another prime (110011222001147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005610500573 + 55005610500574.
It is an arithmetic number, because the mean of its divisors is an integer number (55005610500574).
Almost surely, 2110011221001147 is an apocalyptic number.
110011221001147 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011221001147 is an equidigital number, since it uses as much as digits as its factorization.
110011221001147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 110011221001147 its reverse (741100122110011), we get a palindrome (851111343111158).
The spelling of 110011221001147 in words is "one hundred ten trillion, eleven billion, two hundred twenty-one million, one thousand, one hundred forty-seven".
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