Base | Representation |
---|---|
bin | 10000000000100011110… |
… | …011000111011101110001 |
3 | 10220011120201020122200221 |
4 | 100000203303013131301 |
5 | 121011012212332012 |
6 | 2201215023013041 |
7 | 142323543445315 |
oct | 20004363073561 |
9 | 3804521218627 |
10 | 1100112230257 |
11 | 394611746277 |
12 | 15926143a181 |
13 | 7c981111801 |
14 | 3b36235db45 |
15 | 1d93a76e507 |
hex | 10023cc7771 |
1100112230257 has 2 divisors, whose sum is σ = 1100112230258. Its totient is φ = 1100112230256.
The previous prime is 1100112230221. The next prime is 1100112230267. The reversal of 1100112230257 is 7520322110011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 603269103616 + 496843126641 = 776704^2 + 704871^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100112230257 - 215 = 1100112197489 is a prime.
It is a super-2 number, since 2×11001122302572 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100112230267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550056115128 + 550056115129.
It is an arithmetic number, because the mean of its divisors is an integer number (550056115129).
Almost surely, 21100112230257 is an apocalyptic number.
It is an amenable number.
1100112230257 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100112230257 is an equidigital number, since it uses as much as digits as its factorization.
1100112230257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 25.
Adding to 1100112230257 its reverse (7520322110011), we get a palindrome (8620434340268).
The spelling of 1100112230257 in words is "one trillion, one hundred billion, one hundred twelve million, two hundred thirty thousand, two hundred fifty-seven".
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