Base | Representation |
---|---|
bin | 10000000000100011110… |
… | …110111110010001101111 |
3 | 10220011120210011000110020 |
4 | 100000203312332101233 |
5 | 121011012442204244 |
6 | 2201215100413223 |
7 | 142323555155550 |
oct | 20004366762157 |
9 | 3804523130406 |
10 | 1100113241199 |
11 | 394612276865 |
12 | 159261847213 |
13 | 7c9813a69bb |
14 | 3b362544327 |
15 | 1d93a8bdd19 |
hex | 10023dbe46f |
1100113241199 has 16 divisors (see below), whose sum is σ = 1676403056640. Its totient is φ = 628621129440.
The previous prime is 1100113241197. The next prime is 1100113241299. The reversal of 1100113241199 is 9911423110011.
It is not a de Polignac number, because 1100113241199 - 21 = 1100113241197 is a prime.
It is a super-3 number, since 3×11001132411993 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100113241197) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 307557 + ... + 1514865.
It is an arithmetic number, because the mean of its divisors is an integer number (104775191040).
Almost surely, 21100113241199 is an apocalyptic number.
1100113241199 is a deficient number, since it is larger than the sum of its proper divisors (576289815441).
1100113241199 is a wasteful number, since it uses less digits than its factorization.
1100113241199 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1250710.
The product of its (nonzero) digits is 1944, while the sum is 33.
The spelling of 1100113241199 in words is "one trillion, one hundred billion, one hundred thirteen million, two hundred forty-one thousand, one hundred ninety-nine".
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