Base | Representation |
---|---|
bin | 110011001110100101… |
… | …1111010111001001011 |
3 | 101111221212201121101021 |
4 | 1212131023322321023 |
5 | 3300300400030443 |
6 | 122312152333311 |
7 | 10643116606612 |
oct | 1463513727113 |
9 | 344855647337 |
10 | 110011330123 |
11 | 42723589652 |
12 | 193a26a4237 |
13 | a4b2966016 |
14 | 54788d2879 |
15 | 2cdd0d49ed |
hex | 199d2fae4b |
110011330123 has 2 divisors, whose sum is σ = 110011330124. Its totient is φ = 110011330122.
The previous prime is 110011330109. The next prime is 110011330127. The reversal of 110011330123 is 321033110011.
It is a strong prime.
It is an emirp because it is prime and its reverse (321033110011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110011330123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110011330097 and 110011330106.
It is not a weakly prime, because it can be changed into another prime (110011330127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005665061 + 55005665062.
It is an arithmetic number, because the mean of its divisors is an integer number (55005665062).
Almost surely, 2110011330123 is an apocalyptic number.
110011330123 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011330123 is an equidigital number, since it uses as much as digits as its factorization.
110011330123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 110011330123 its reverse (321033110011), we get a palindrome (431044440134).
The spelling of 110011330123 in words is "one hundred ten billion, eleven million, three hundred thirty thousand, one hundred twenty-three".
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