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1100122121003 = 53201110321741
BaseRepresentation
bin10000000000100100011…
…000110110001100101011
310220011121101212011020212
4100000210120312030223
5121011022230333003
62201220015011335
7142324023511313
oct20004430661453
93804541764225
101100122121003
11394617291344
12159264809b4b
137c983195719
143b3637b6443
151d93b574dd8
hex1002463632b

1100122121003 has 8 divisors (see below), whose sum is σ = 1121436624816. Its totient is φ = 1078828264800.

The previous prime is 1100122120961. The next prime is 1100122121027. The reversal of 1100122121003 is 3001212210011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1100122121003 - 216 = 1100122055467 is a prime.

It is a super-2 number, since 2×11001221210032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100122121093) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5054288 + ... + 5267453.

It is an arithmetic number, because the mean of its divisors is an integer number (140179578102).

Almost surely, 21100122121003 is an apocalyptic number.

1100122121003 is a deficient number, since it is larger than the sum of its proper divisors (21314503813).

1100122121003 is a wasteful number, since it uses less digits than its factorization.

1100122121003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10323805.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 1100122121003 its reverse (3001212210011), we get a palindrome (4101334331014).

The spelling of 1100122121003 in words is "one trillion, one hundred billion, one hundred twenty-two million, one hundred twenty-one thousand, three".

Divisors: 1 53 2011 106583 10321741 547052273 20757021151 1100122121003