1100132031553 has 4 divisors (see below), whose sum is σ = 1100326647508. Its totient is φ = 1099937415600.

The previous prime is 1100132031529. The next prime is 1100132031617. The reversal of 1100132031553 is 3551302310011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 925919289009 + 174212742544 = 962247^2 + 417388^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100132031553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100132031503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97299498 + ... + 97310803.

It is an arithmetic number, because the mean of its divisors is an integer number (275081661877).

Almost surely, 2^{1100132031553} is an apocalyptic number.

It is an amenable number.

1100132031553 is a deficient number, since it is larger than the sum of its proper divisors (194615955).

1100132031553 is an equidigital number, since it uses as much as digits as its factorization.

1100132031553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 194615954.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 1100132031553 its reverse (3551302310011), we get a palindrome (4651434341564).

The spelling of 1100132031553 in words is "one trillion, one hundred billion, one hundred thirty-two million, thirty-one thousand, five hundred fifty-three".