Base | Representation |
---|---|
bin | 11001000000111001110010… |
… | …100000000100111100001100 |
3 | 112102112011022222202112222120 |
4 | 121000321302200010330030 |
5 | 103404424030103044322 |
6 | 1025551212243212540 |
7 | 32113122661134222 |
oct | 3100716240047414 |
9 | 472464288675876 |
10 | 110013213331212 |
11 | 32065383983534 |
12 | 1040936a677150 |
13 | 4950280917339 |
14 | 1d2494cb5cb12 |
15 | caba69753a5c |
hex | 640e72804f0c |
110013213331212 has 24 divisors (see below), whose sum is σ = 256697951467776. Its totient is φ = 36671006296848.
The previous prime is 110013213331211. The next prime is 110013213331237. The reversal of 110013213331212 is 212133312310011.
It is not an unprimeable number, because it can be changed into a prime (110013213331211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 763408 + ... + 14852919.
It is an arithmetic number, because the mean of its divisors is an integer number (10695747977824).
Almost surely, 2110013213331212 is an apocalyptic number.
110013213331212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
110013213331212 is an abundant number, since it is smaller than the sum of its proper divisors (146684738136564).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110013213331212 is a wasteful number, since it uses less digits than its factorization.
110013213331212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16203397 (or 16203395 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 110013213331212 its reverse (212133312310011), we get a palindrome (322146525641223).
The spelling of 110013213331212 in words is "one hundred ten trillion, thirteen billion, two hundred thirteen million, three hundred thirty-one thousand, two hundred twelve".
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