Base | Representation |
---|---|
bin | 11001000000111001111000… |
… | …011100010111010001001011 |
3 | 112102112011120221100022200001 |
4 | 121000321320130113101023 |
5 | 103404424231113133003 |
6 | 1025551230204023431 |
7 | 32113125311365060 |
oct | 3100717034272113 |
9 | 472464527308601 |
10 | 110013313021003 |
11 | 32065425182997 |
12 | 10409397b31b77 |
13 | 495029847c892 |
14 | 1d2495c0acc67 |
15 | caba7339661d |
hex | 640e7871744b |
110013313021003 has 4 divisors (see below), whose sum is σ = 125729500595440. Its totient is φ = 94297125446568.
The previous prime is 110013313020979. The next prime is 110013313021021. The reversal of 110013313021003 is 300120313310011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110013313021003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (110013313021033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7858093787208 + ... + 7858093787221.
It is an arithmetic number, because the mean of its divisors is an integer number (31432375148860).
Almost surely, 2110013313021003 is an apocalyptic number.
110013313021003 is a deficient number, since it is larger than the sum of its proper divisors (15716187574437).
110013313021003 is an equidigital number, since it uses as much as digits as its factorization.
110013313021003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15716187574436.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 110013313021003 its reverse (300120313310011), we get a palindrome (410133626331014).
The spelling of 110013313021003 in words is "one hundred ten trillion, thirteen billion, three hundred thirteen million, twenty-one thousand, three".
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