Base | Representation |
---|---|
bin | 11001000000111001111111… |
… | …101010101010111111011001 |
3 | 112102112011220101101110220002 |
4 | 121000321333222222333121 |
5 | 103404430003124243223 |
6 | 1025551250213342345 |
7 | 32113131312450362 |
oct | 3100717752527731 |
9 | 472464811343802 |
10 | 110013434212313 |
11 | 320654876287a5 |
12 | 104094106379b5 |
13 | 49502b7602b08 |
14 | 1d24970218b69 |
15 | caba7dd34e28 |
hex | 640e7faaafd9 |
110013434212313 has 2 divisors, whose sum is σ = 110013434212314. Its totient is φ = 110013434212312.
The previous prime is 110013434212289. The next prime is 110013434212349. The reversal of 110013434212313 is 313212434310011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109983943706329 + 29490505984 = 10487323^2 + 171728^2 .
It is a cyclic number.
It is not a de Polignac number, because 110013434212313 - 220 = 110013433163737 is a prime.
It is not a weakly prime, because it can be changed into another prime (110013434412313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006717106156 + 55006717106157.
It is an arithmetic number, because the mean of its divisors is an integer number (55006717106157).
Almost surely, 2110013434212313 is an apocalyptic number.
It is an amenable number.
110013434212313 is a deficient number, since it is larger than the sum of its proper divisors (1).
110013434212313 is an equidigital number, since it uses as much as digits as its factorization.
110013434212313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 110013434212313 its reverse (313212434310011), we get a palindrome (423225868522324).
The spelling of 110013434212313 in words is "one hundred ten trillion, thirteen billion, four hundred thirty-four million, two hundred twelve thousand, three hundred thirteen".
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