1100197825897 has 2 divisors, whose sum is σ = 1100197825898. Its totient is φ = 1100197825896.

The previous prime is 1100197825879. The next prime is 1100197825921. The reversal of 1100197825897 is 7985287910011.

Together with previous prime (1100197825879) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 858641303641 + 241556522256 = 926629^2 + 491484^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100197825897 is a prime.

It is a super-2 number, since 2×1100197825897² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100197325897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550098912948 + 550098912949.

It is an arithmetic number, because the mean of its divisors is an integer number (550098912949).

Almost surely, 2^{1100197825897} is an apocalyptic number.

It is an amenable number.

1100197825897 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100197825897 is an equidigital number, since it uses as much as digits as its factorization.

1100197825897 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2540160, while the sum is 58.

The spelling of 1100197825897 in words is "one trillion, one hundred billion, one hundred ninety-seven million, eight hundred twenty-five thousand, eight hundred ninety-seven".