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1100200221283 is a prime number
BaseRepresentation
bin10000000000101001000…
…010110001101001100011
310220011210211211001200211
4100000221002301221203
5121011202224040113
62201231444554551
7142325662403032
oct20005102615143
93804724731624
101100200221283
11394657385229
121592869b2a57
137c99640c1c7
143b36dd06719
151d943350b3d
hex100290b1a63

1100200221283 has 2 divisors, whose sum is σ = 1100200221284. Its totient is φ = 1100200221282.

The previous prime is 1100200221277. The next prime is 1100200221319. The reversal of 1100200221283 is 3821220020011.

It is a weak prime.

It is an emirp because it is prime and its reverse (3821220020011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100200221283 - 217 = 1100200090211 is a prime.

It is a super-2 number, since 2×11002002212832 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100200221203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550100110641 + 550100110642.

It is an arithmetic number, because the mean of its divisors is an integer number (550100110642).

Almost surely, 21100200221283 is an apocalyptic number.

1100200221283 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100200221283 is an equidigital number, since it uses as much as digits as its factorization.

1100200221283 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 1100200221283 its reverse (3821220020011), we get a palindrome (4921420241294).

The spelling of 1100200221283 in words is "one trillion, one hundred billion, two hundred million, two hundred twenty-one thousand, two hundred eighty-three".