Search a number
-
+
1100202001081 is a prime number
BaseRepresentation
bin10000000000101001001…
…001100100001010111001
310220011210222011111010021
4100000221021210022321
5121011203203013311
62201231551050441
7142326013464661
oct20005111441271
93804728144107
101100202001081
11394658390437
12159287510a21
137c9968b3341
143b37024b1a1
151d9435a3171
hex100292642b9

1100202001081 has 2 divisors, whose sum is σ = 1100202001082. Its totient is φ = 1100202001080.

The previous prime is 1100202001069. The next prime is 1100202001127. The reversal of 1100202001081 is 1801002020011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 672701793856 + 427500207225 = 820184^2 + 653835^2 .

It is an emirp because it is prime and its reverse (1801002020011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100202001081 - 25 = 1100202001049 is a prime.

It is a super-2 number, since 2×11002020010812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100202001051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550101000540 + 550101000541.

It is an arithmetic number, because the mean of its divisors is an integer number (550101000541).

Almost surely, 21100202001081 is an apocalyptic number.

It is an amenable number.

1100202001081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100202001081 is an equidigital number, since it uses as much as digits as its factorization.

1100202001081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 1100202001081 its reverse (1801002020011), we get a palindrome (2901204021092).

The spelling of 1100202001081 in words is "one trillion, one hundred billion, two hundred two million, one thousand, eighty-one".