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110021000113 is a prime number
BaseRepresentation
bin110011001110111000…
…0110011101110110001
3101111222112220220010001
41212131300303232301
53300310334000423
6122313135510001
710643265033163
oct1463560635661
9344875826101
10110021000113
1142728a93882
12193a5988301
13a4b49705cb
145479ccc933
152cddd94cad
hex199dc33bb1

110021000113 has 2 divisors, whose sum is σ = 110021000114. Its totient is φ = 110021000112.

The previous prime is 110021000099. The next prime is 110021000119. The reversal of 110021000113 is 311000120011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73588497984 + 36432502129 = 271272^2 + 190873^2 .

It is a cyclic number.

It is not a de Polignac number, because 110021000113 - 225 = 109987445681 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110021000113.

It is not a weakly prime, because it can be changed into another prime (110021000119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010500056 + 55010500057.

It is an arithmetic number, because the mean of its divisors is an integer number (55010500057).

Almost surely, 2110021000113 is an apocalyptic number.

It is an amenable number.

110021000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110021000113 is an equidigital number, since it uses as much as digits as its factorization.

110021000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 110021000113 its reverse (311000120011), we get a palindrome (421021120124).

The spelling of 110021000113 in words is "one hundred ten billion, twenty-one million, one hundred thirteen", and thus it is an aban number.