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1100210112322 = 2550105056161
BaseRepresentation
bin10000000000101001101…
…000100000011101000010
310220011211112102120122121
4100000221220200131002
5121011212242043242
62201232440554454
7142326142436626
oct20005150403502
93804745376577
101100210112322
11394661a20542
1215928a182a2a
137c9984932a9
143b37135d186
151d944156667
hex10029a20742

1100210112322 has 4 divisors (see below), whose sum is σ = 1650315168486. Its totient is φ = 550105056160.

The previous prime is 1100210112301. The next prime is 1100210112343. The reversal of 1100210112322 is 2232110120011.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1100210112301) and next prime (1100210112343).

It can be written as a sum of positive squares in only one way, i.e., 657784259521 + 442425852801 = 811039^2 + 665151^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1100210112296 and 1100210112305.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275052528079 + ... + 275052528082.

Almost surely, 21100210112322 is an apocalyptic number.

1100210112322 is a deficient number, since it is larger than the sum of its proper divisors (550105056164).

1100210112322 is an equidigital number, since it uses as much as digits as its factorization.

1100210112322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 550105056163.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1100210112322 its reverse (2232110120011), we get a palindrome (3332320232333).

The spelling of 1100210112322 in words is "one trillion, one hundred billion, two hundred ten million, one hundred twelve thousand, three hundred twenty-two".

Divisors: 1 2 550105056161 1100210112322