Search a number
-
+
1100210207 = 29372274517
BaseRepresentation
bin100000110010011…
…1110000000011111
32211200020110200012
41001210332000133
54223123211312
6301101153435
736156426635
oct10144760037
92750213605
101100210207
11515049238
1226855b87b
13146c25575
14a6195355
15668c8322
hex4193e01f

1100210207 has 16 divisors (see below), whose sum is σ = 1174318560. Its totient is φ = 1028780928.

The previous prime is 1100210179. The next prime is 1100210239. The reversal of 1100210207 is 7020120011.

It is a cyclic number.

It is not a de Polignac number, because 1100210207 - 28 = 1100209951 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100210191 and 1100210200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100210297) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 241313 + ... + 245829.

It is an arithmetic number, because the mean of its divisors is an integer number (73394910).

Almost surely, 21100210207 is an apocalyptic number.

1100210207 is a deficient number, since it is larger than the sum of its proper divisors (74108353).

1100210207 is a wasteful number, since it uses less digits than its factorization.

1100210207 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4810.

The product of its (nonzero) digits is 28, while the sum is 14.

The square root of 1100210207 is about 33169.4167419326. The cubic root of 1100210207 is about 1032.3458665732.

Adding to 1100210207 its reverse (7020120011), we get a palindrome (8120330218).

The spelling of 1100210207 in words is "one billion, one hundred million, two hundred ten thousand, two hundred seven".

Divisors: 1 29 37 227 1073 4517 6583 8399 130993 167129 243571 1025359 4846741 29735411 37938283 1100210207