110021114213433 has 32 divisors (see below), whose sum is σ = 172585356249600. Its totient is φ = 69031569454848.

The previous prime is 110021114213411. The next prime is 110021114213443. The reversal of 110021114213433 is 334312411120011.

110021114213433 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 2 + 1 + 1 + 14 + 213 + 433 = 666.

It is not a de Polignac number, because 110021114213433 - 2⁵ = 110021114213401 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 110021114213397 and 110021114213406.

It is not an unprimeable number, because it can be changed into a prime (110021114213443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 22726035 + ... + 27138807.

It is an arithmetic number, because the mean of its divisors is an integer number (5393292382800).

Almost surely, 2^{110021114213433} is an apocalyptic number.

It is an amenable number.

110021114213433 is a deficient number, since it is larger than the sum of its proper divisors (62564242036167).

110021114213433 is a wasteful number, since it uses less digits than its factorization.

110021114213433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4467118 (or 4467112 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 110021114213433 its reverse (334312411120011), we get a palindrome (444333525333444).

The spelling of 110021114213433 in words is "one hundred ten trillion, twenty-one billion, one hundred fourteen million, two hundred thirteen thousand, four hundred thirty-three".