Base | Representation |
---|---|
bin | 10000000000101001110… |
… | …000000101101110101011 |
3 | 10220011211200011120020201 |
4 | 100000221300011232223 |
5 | 121011213244200021 |
6 | 2201232551333031 |
7 | 142326165355633 |
oct | 20005160055653 |
9 | 3804750146221 |
10 | 1100212100011 |
11 | 394663058962 |
12 | 15928a981177 |
13 | 7c998a0ac3b |
14 | 3b3717196c3 |
15 | 1d9443ea591 |
hex | 10029c05bab |
1100212100011 has 4 divisors (see below), whose sum is σ = 1100743862400. Its totient is φ = 1099680337624.
The previous prime is 1100212099933. The next prime is 1100212100069. The reversal of 1100212100011 is 1100012120011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1100212100011 - 213 = 1100212091819 is a prime.
It is a super-2 number, since 2×11002121000112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1100212100081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 265878091 + ... + 265882228.
It is an arithmetic number, because the mean of its divisors is an integer number (275185965600).
Almost surely, 21100212100011 is an apocalyptic number.
1100212100011 is a deficient number, since it is larger than the sum of its proper divisors (531762389).
1100212100011 is an equidigital number, since it uses as much as digits as its factorization.
1100212100011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 531762388.
The product of its (nonzero) digits is 4, while the sum is 10.
Adding to 1100212100011 its reverse (1100012120011), we get a palindrome (2200224220022).
The spelling of 1100212100011 in words is "one trillion, one hundred billion, two hundred twelve million, one hundred thousand, eleven".
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