Search a number
-
+
110021220012409 is a prime number
BaseRepresentation
bin11001000001000001001111…
…101111001001000101111001
3112102112220222222202002202121
4121001001033233021011321
5103410041424310344114
61025555014542201241
732113525252612126
oct3101011757110571
9472486888662677
10110021220012409
11320688124a4632
121040aa23b83221
134950c58659514
141d250ac28574d
15cabd8761da24
hex64104fbc9179

110021220012409 has 2 divisors, whose sum is σ = 110021220012410. Its totient is φ = 110021220012408.

The previous prime is 110021220012383. The next prime is 110021220012419. The reversal of 110021220012409 is 904210022120011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93891196924009 + 16130023088400 = 9689747^2 + 4016220^2 .

It is an emirp because it is prime and its reverse (904210022120011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110021220012409 - 223 = 110021211623801 is a prime.

It is a super-2 number, since 2×1100212200124092 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110021220012419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010610006204 + 55010610006205.

It is an arithmetic number, because the mean of its divisors is an integer number (55010610006205).

Almost surely, 2110021220012409 is an apocalyptic number.

It is an amenable number.

110021220012409 is a deficient number, since it is larger than the sum of its proper divisors (1).

110021220012409 is an equidigital number, since it uses as much as digits as its factorization.

110021220012409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

The spelling of 110021220012409 in words is "one hundred ten trillion, twenty-one billion, two hundred twenty million, twelve thousand, four hundred nine".