Base | Representation |
---|---|
bin | 11001000001000001001111… |
… | …101111001001010101001011 |
3 | 112102112220222222202011002211 |
4 | 121001001033233021111023 |
5 | 103410041424310412022 |
6 | 1025555014542205551 |
7 | 32113525252615024 |
oct | 3101011757112513 |
9 | 472486888664084 |
10 | 110021220013387 |
11 | 320688124a5341 |
12 | 1040aa23b838b7 |
13 | 4950c58659ab7 |
14 | 1d250ac285c4b |
15 | cabd8761de77 |
hex | 64104fbc954b |
110021220013387 has 2 divisors, whose sum is σ = 110021220013388. Its totient is φ = 110021220013386.
The previous prime is 110021220013301. The next prime is 110021220013451. The reversal of 110021220013387 is 783310022120011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110021220013387 is a prime.
It is not a weakly prime, because it can be changed into another prime (110021220016387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010610006693 + 55010610006694.
It is an arithmetic number, because the mean of its divisors is an integer number (55010610006694).
Almost surely, 2110021220013387 is an apocalyptic number.
110021220013387 is a deficient number, since it is larger than the sum of its proper divisors (1).
110021220013387 is an equidigital number, since it uses as much as digits as its factorization.
110021220013387 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 31.
Adding to 110021220013387 its reverse (783310022120011), we get a palindrome (893331242133398).
The spelling of 110021220013387 in words is "one hundred ten trillion, twenty-one billion, two hundred twenty million, thirteen thousand, three hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •