Base | Representation |
---|---|
bin | 10000000000101001110… |
… | …011101000110001001011 |
3 | 10220011211201220210220101 |
4 | 100000221303220301023 |
5 | 121011214013424323 |
6 | 2201233023310231 |
7 | 142326206311105 |
oct | 20005163506113 |
9 | 3804751823811 |
10 | 1100213029963 |
11 | 394663633613 |
12 | 15928b14b377 |
13 | 7c998c752c8 |
14 | 3b3718bc575 |
15 | 1d944530dad |
hex | 10029ce8c4b |
1100213029963 has 2 divisors, whose sum is σ = 1100213029964. Its totient is φ = 1100213029962.
The previous prime is 1100213029943. The next prime is 1100213030039. The reversal of 1100213029963 is 3699203120011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100213029963 - 237 = 962774076491 is a prime.
It is a super-2 number, since 2×11002130299632 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100213029943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550106514981 + 550106514982.
It is an arithmetic number, because the mean of its divisors is an integer number (550106514982).
Almost surely, 21100213029963 is an apocalyptic number.
1100213029963 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100213029963 is an equidigital number, since it uses as much as digits as its factorization.
1100213029963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 37.
Adding to 1100213029963 its reverse (3699203120011), we get a palindrome (4799416149974).
It can be divided in two parts, 110021 and 3029963, that added together give a square (3139984 = 17722).
The spelling of 1100213029963 in words is "one trillion, one hundred billion, two hundred thirteen million, twenty-nine thousand, nine hundred sixty-three".
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