Base | Representation |
---|---|
bin | 110011001110111010… |
… | …0101010110011100011 |
3 | 101111222121211022100012 |
4 | 1212131310222303203 |
5 | 3300311113342011 |
6 | 122313213315135 |
7 | 10643306446523 |
oct | 1463564526343 |
9 | 344877738305 |
10 | 110022012131 |
11 | 42729615159 |
12 | 193a6195aab |
13 | a4b4c36135 |
14 | 547a0b3683 |
15 | 2cddee4a8b |
hex | 199dd2ace3 |
110022012131 has 2 divisors, whose sum is σ = 110022012132. Its totient is φ = 110022012130.
The previous prime is 110022012109. The next prime is 110022012193. The reversal of 110022012131 is 131210220011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110022012131 - 218 = 110021749987 is a prime.
It is a super-2 number, since 2×1100220121312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110022012101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55011006065 + 55011006066.
It is an arithmetic number, because the mean of its divisors is an integer number (55011006066).
Almost surely, 2110022012131 is an apocalyptic number.
110022012131 is a deficient number, since it is larger than the sum of its proper divisors (1).
110022012131 is an equidigital number, since it uses as much as digits as its factorization.
110022012131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 110022012131 its reverse (131210220011), we get a palindrome (241232232142).
The spelling of 110022012131 in words is "one hundred ten billion, twenty-two million, twelve thousand, one hundred thirty-one".
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