Base | Representation |
---|---|
bin | 10100011111100100… |
… | …11111101001010101 |
3 | 1001101202210102111020 |
4 | 22033302133221111 |
5 | 140013043011201 |
6 | 5015425431353 |
7 | 536435056110 |
oct | 121762375125 |
9 | 31352712436 |
10 | 11002313301 |
11 | 4736578911 |
12 | 217079b559 |
13 | 1064557575 |
14 | 765313577 |
15 | 445d99a36 |
hex | 28fc9fa55 |
11002313301 has 32 divisors (see below), whose sum is σ = 17093203200. Its totient is φ = 6164281344.
The previous prime is 11002313239. The next prime is 11002313339. The reversal of 11002313301 is 10331320011.
It is not a de Polignac number, because 11002313301 - 211 = 11002311253 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11002313341) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2527675 + ... + 2532023.
It is an arithmetic number, because the mean of its divisors is an integer number (534162600).
Almost surely, 211002313301 is an apocalyptic number.
It is an amenable number.
11002313301 is a deficient number, since it is larger than the sum of its proper divisors (6090889899).
11002313301 is a wasteful number, since it uses less digits than its factorization.
11002313301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6685.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11002313301 its reverse (10331320011), we get a palindrome (21333633312).
The spelling of 11002313301 in words is "eleven billion, two million, three hundred thirteen thousand, three hundred one".
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