Base | Representation |
---|---|
bin | 1010000000011011001011… |
… | …1000101010100111011011 |
3 | 1102221211011001002112111202 |
4 | 2200012302320222213123 |
5 | 2420230420041202443 |
6 | 35222234414344415 |
7 | 2213620015466162 |
oct | 240066270524733 |
9 | 42854131075452 |
10 | 11002412444123 |
11 | 3562107aa0991 |
12 | 12984117bb10b |
13 | 61a6a5178b99 |
14 | 2a073bb143d9 |
15 | 1412e838c7b8 |
hex | a01b2e2a9db |
11002412444123 has 2 divisors, whose sum is σ = 11002412444124. Its totient is φ = 11002412444122.
The previous prime is 11002412444039. The next prime is 11002412444141. The reversal of 11002412444123 is 32144421420011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11002412444123 is a prime.
It is not a weakly prime, because it can be changed into another prime (11002412444923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501206222061 + 5501206222062.
It is an arithmetic number, because the mean of its divisors is an integer number (5501206222062).
Almost surely, 211002412444123 is an apocalyptic number.
11002412444123 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002412444123 is an equidigital number, since it uses as much as digits as its factorization.
11002412444123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 11002412444123 its reverse (32144421420011), we get a palindrome (43146833864134).
The spelling of 11002412444123 in words is "eleven trillion, two billion, four hundred twelve million, four hundred forty-four thousand, one hundred twenty-three".
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