Base | Representation |
---|---|
bin | 1010000000011101011010… |
… | …0100011110011110100111 |
3 | 1102221212200202121222221000 |
4 | 2200013112210132132213 |
5 | 2420233131322200203 |
6 | 35222414042324343 |
7 | 2213640605316642 |
oct | 240072644363647 |
9 | 42855622558830 |
10 | 11003011131303 |
11 | 3562394a32484 |
12 | 129855a1b96b3 |
13 | 61a76c205059 |
14 | 2a0797438a59 |
15 | 141330beb4a3 |
hex | a01d691e7a7 |
11003011131303 has 16 divisors (see below), whose sum is σ = 16300808392960. Its totient is φ = 7335317731608.
The previous prime is 11003011131263. The next prime is 11003011131319. The reversal of 11003011131303 is 30313111030011.
11003011131303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11003011131303 - 217 = 11003011000231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11003011131403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15895326 + ... + 16573092.
It is an arithmetic number, because the mean of its divisors is an integer number (1018800524560).
Almost surely, 211003011131303 is an apocalyptic number.
11003011131303 is a deficient number, since it is larger than the sum of its proper divisors (5297797261657).
11003011131303 is an equidigital number, since it uses as much as digits as its factorization.
11003011131303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1279043 (or 1279037 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 18.
Adding to 11003011131303 its reverse (30313111030011), we get a palindrome (41316122161314).
The spelling of 11003011131303 in words is "eleven trillion, three billion, eleven million, one hundred thirty-one thousand, three hundred three".
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