11003031133121 has 2 divisors, whose sum is σ = 11003031133122. Its totient is φ = 11003031133120.

The previous prime is 11003031133097. The next prime is 11003031133153. The reversal of 11003031133121 is 12133113030011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10877760441025 + 125270692096 = 3298145^2 + 353936^2 .

It is an emirp because it is prime and its reverse (12133113030011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11003031133121 - 2¹⁸ = 11003030870977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11003031133093 and 11003031133102.

It is not a weakly prime, because it can be changed into another prime (11003031133321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501515566560 + 5501515566561.

It is an arithmetic number, because the mean of its divisors is an integer number (5501515566561).

Almost surely, 2^{11003031133121} is an apocalyptic number.

It is an amenable number.

11003031133121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11003031133121 is an equidigital number, since it uses as much as digits as its factorization.

11003031133121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 11003031133121 its reverse (12133113030011), we get a palindrome (23136144163132).

The spelling of 11003031133121 in words is "eleven trillion, three billion, thirty-one million, one hundred thirty-three thousand, one hundred twenty-one".