Search a number
-
+
110031101202017 is a prime number
BaseRepresentation
bin11001000001001010011100…
…101100111000111001100001
3112102120212111121221112200002
4121001022130230320321201
5103410222143401431032
61030003331242305345
732114325155416112
oct3101123454707141
9472525447845602
10110031101202017
1132071a2313a636
12104109211b8255
134951b71848388
141d2576871c209
15cac264d5d862
hex64129cb38e61

110031101202017 has 2 divisors, whose sum is σ = 110031101202018. Its totient is φ = 110031101202016.

The previous prime is 110031101201977. The next prime is 110031101202023. The reversal of 110031101202017 is 710202101130011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83592181551376 + 26438919650641 = 9142876^2 + 5141879^2 .

It is a cyclic number.

It is not a de Polignac number, because 110031101202017 - 220 = 110031100153441 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110031101202017.

It is not a weakly prime, because it can be changed into another prime (110031101202317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55015550601008 + 55015550601009.

It is an arithmetic number, because the mean of its divisors is an integer number (55015550601009).

Almost surely, 2110031101202017 is an apocalyptic number.

It is an amenable number.

110031101202017 is a deficient number, since it is larger than the sum of its proper divisors (1).

110031101202017 is an equidigital number, since it uses as much as digits as its factorization.

110031101202017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 20.

Adding to 110031101202017 its reverse (710202101130011), we get a palindrome (820233202332028).

The spelling of 110031101202017 in words is "one hundred ten trillion, thirty-one billion, one hundred one million, two hundred two thousand, seventeen".